16 August 2015

Basic information of examination HTAT

HTAT (Head Teacher Aptitude Test) 2015 Exam details:

Exam Name: Head Teacher Aptitude Test HTAT 2015
News-letter announcement: 07/08/2015

Important Dates:

Online application date: 10/08/2015
Online Application deadline: 19/08/2015
Exam date: 20/09/2015


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15 August 2015

સર્વે  મારા બ્લોગ જોનાર  શિક્ષક્ગણ  તેમજ વિદ્યાર્થી  મિત્રો ને 69 HAPPY INDEPENDENCE DAY 

20 June 2015

Basic TET information

TET Eligibility details

Educational qualification :

1. For Primary Teacher :
  • Your minimum educational qualification should be Inter passed out from recognized university/board.
  • You should have a Diploma degree in Elementary Education from recognized university and should be approved from the NCTE.
  • Your minimum marks in Inter should be 50%.
  • Your minimum marks in Diploma should be 45%.
2. For Elementary Teacher :
  • Your minimum educational qualification should be Graduation passed out from recognized university.
  • You should have a B.Ed degree from recognized university and should be approved from the NCTE.
  • Your minimum marks in Graduation should be 55%.
  • Your minimum marks in B.Ed should be 50%.
NOTE :
  • To appear in this exam,there is No age Limit.
  • SC/ST candidates will get 5% of Marks Relaxations.
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Short Mathematics Tricks
Squaring
In this simple trick we need to modify the equation and make the units digit zero. After all it is easy to multiply when units digit is zero.
For example - Find square of 43
= (43+3) × (43-3) + (3×3)
=(46×40) + 9
= (460×4) + 9
= 1840 + 9 = 1849
Multiplication with 5
Simply multiply the number by 10 and then divide it by 2.
For example 99×5= 990/2= 495
Multiplication with 99

Multiply the number with 100 and then minus same number from the result. Let's take an example
Multiply 32×99 = 3200 - 32 = 3168

Square root
Best method to find square root of large numbers is by dividing the number into parts. Let's take an example
Find square √ 1936
√ 1936 = √ 4 × √ 484 = √ 4 × √ 4 × √ 121 = 2×2×11 = 44

Time and Work
Every question in in time and work chapter can be solved easily by finding efficiency of workers or subject (such as pipes).

For example - A takes 10 days to complete a job. B takes 20 days to complete the same job. In how many days they will complete the job if they work together ?
A's efficiency = 100/10 = 10% per day
B's efficiency = 100/20 = 5% per days
A and B can do 15% of the work in a day if they work together. So they can do the whole job in 100/15 = 6.66 days or 6 days and 18 hours.

Estimation
That's the most important technique. This is not a secret that every successful candidate is using this technique during exams.

Example - 112 × 92
Simply 112 × 9 = 1008
Add a zero 10080 and then add 224 to 10080.
Answer is 10304

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